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-5x^2+4x+57=0
a = -5; b = 4; c = +57;
Δ = b2-4ac
Δ = 42-4·(-5)·57
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-34}{2*-5}=\frac{-38}{-10} =3+4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+34}{2*-5}=\frac{30}{-10} =-3 $
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